That’s a lot, and some of these interrupts only have a few scanlines worth of time that they may operate in. We can’t rely on $D012 to identify what to do anymore; instead we’ll keep a separate counter, increment it on each IRQ, and loop it around at the end. We can then also use that counter as an index into various arrays to efficiently handle many of the differences.
Number (3): Everything in this space must add up to 3. The answer is 4-3, placed horizontally.
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76% 4 == 0,满足约束
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